RRB JE 2024 answer key: The Railway Recruitment Board (RRB) has announced that today, December 28, marks the final day to submit objections for the RRB JE 2024 Answer Key. This recruitment drive, aimed at filling 7,951 vacancies, includes positions such as Junior Engineer (JE), Depot Material Superintendent (DMS), Chemical & Metallurgical Assistant (CMA), and others.
Candidates who participated in the recruitment exams must submit their objections by 11:55 PM through the official RRB websites. This process allows candidates to ensure accuracy in the evaluation and transparency in the recruitment process.
How to Submit Objections for the RRB JE 2024 Answer Key
To challenge the RRB JE 2024 answer key, candidates need their login credentials, including the registration number and date of birth. Supporting documents must be uploaded to substantiate the objection. The RRB has outlined that:
- An objection fee of ₹50 per challenge must be paid online.
- Additional bank charges may apply.
- If the objection is found valid, the paid fee (minus applicable charges) will be refunded to the same account used for the original payment.
This streamlined process ensures that candidates have a fair chance to rectify discrepancies in the answer key.
RRB JE Recruitment Drive 2024: Key Highlights
The 2024 RRB recruitment aims to fill a total of 7,951 vacancies, categorized as follows:
- Junior Engineer (JE), Depot Material Superintendent (DMS), and Chemical & Metallurgical Assistant (CMA): 7,934 posts
- Chemical Supervisor, Research, and Metallurgical Supervisor: 17 posts
Candidates who clear the first stage, CBT 1, will progress to CBT 2, followed by document verification and medical examination rounds.
This comprehensive recruitment process ensures that qualified candidates are selected for critical roles in the railway department.
How to Calculate Probable Scores
To estimate your performance in the RRB JE 2024 exam, follow the official scoring formula:
Marks Scored=(Number of Correct Answers×1)−(Number of Incorrect Answers×13)\text{Marks Scored} = (\text{Number of Correct Answers} \times 1) – (\text{Number of Incorrect Answers} \times \frac{1}{3})Marks Scored=(Number of Correct Answers×1)−(Number of Incorrect Answers×31)
Example:
- Correct Answers: 85
- Incorrect Answers: 10
Marks Scored=(85×1)−(10×13)=85−3.33=81.67\text{Marks Scored} = (85 \times 1) – (10 \times \frac{1}{3}) = 85 – 3.33 = 81.67Marks Scored=(85×1)−(10×31)=85−3.33=81.67
Using this formula, candidates can calculate their estimated score and determine their chances of progressing to the next stage.
Next Steps for Candidates
As the answer key objection window closes, candidates should focus on preparing for the subsequent rounds, including CBT 2 and document verification. The RRB ensures transparency throughout the process, allowing candidates to contest discrepancies and ensure fair evaluation.
Stay updated with the latest notifications on the official RRB websites to track further developments in the recruitment process.
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